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fluidistic
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Homework Statement
I'm having a hard time to solve the following DE using an integrating factor, I'm asked to find one and solve the DE.
[itex](x+y^2)-2xyy'=0[/itex].
Homework Equations
The Attempt at a Solution
If I call u=u(x) (I assume the integrating factor depends only on x, not on y), the following must hold: [itex]\frac{\partial}{\partial y} [u\cdot (x+y^2)]= \frac{\partial}{\partial x} (-2xyu)[/itex]. This lead me to [itex]2yu=-2(y'ux+yu'x+yu)[/itex]. I tried to find u(x) but this lead me nowhere. Any idea on how to proceed?
Edit: Nevermind guys I got it! I had to assume that y didn't depend on x. I reached the result that wolfram alpha gives so problem solved!
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