First and Second Order Differential Equation

In summary, the conversation discusses two problems involving differential equations and solutions. It is shown that phi(t) = e^2t is a solution of y' - 2y = 0 and that C*phi(t) is also a solution for any constant C. Similarly, it is shown that phi(t) = 1/t is a solution of y' + y^2 = 0 for t>0 but that y = c*phi(t) is not a solution unless c = 0 or c = 1. The term "show" in this context means to substitute the given solutions into the differential equations and verify their validity.
  • #1
aznkid310
109
1

Homework Statement



a) Show that phi(t) = e^2t is a solution of y' - 2y = 0 and that C*phi(t) is also a solution for any constant C

b) Show that phi(t) = 1/t is a solution of y' + y^2 = 0 for t>0 but that y = c*phi(t) is not a solution unless c = 0 or c = 1

Homework Equations



What do they mean by "show'?

The Attempt at a Solution



a) dy/2y = dt

(1/2)ln(y) = t + C

y = e^(2t + c) = Ce^2t, where c is any constant

Now what?

b) -dy/y^2 = dt

1/y = t + C

y = 1/(t + C)

Again, how do i show?
 
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  • #2
Hi aznkid310! :smile:
aznkid310 said:
a) dy/2y = dt

(1/2)ln(y) = t + C

y = e^(2t + c) = Ce^2t, where c is any constant

Now what?

That's it! You've done it! :smile:

b) -dy/y^2 = dt

1/y = t + C

y = 1/(t + C)

Again, how do i show?

Again, that's it … except of course you still have to make the obvious remark that C/t is not a solution! :smile:
What do they mean by "show'?

I think they just mean "prove". :smile:

Alternatively, they may mean "no need to pretend you don't know the answer … just plug the answer straight into the original equation and confirm that it works" :rolleyes:

Better ask your teacher/tutor/professor which one it is! :smile:
 
  • #3
'Show' just means substitute the given solutions into the differential equations and verify that they work or not. You don't have to solve the differential equation.
 

Related to First and Second Order Differential Equation

1. What is the difference between first and second order differential equations?

First order differential equations involve only one independent variable and its derivative, while second order differential equations involve two independent variables and their derivatives.

2. What is the general form of a first order differential equation?

The general form of a first order differential equation is dy/dx = f(x,y), where y is the dependent variable and x is the independent variable.

3. How do you solve a first order differential equation?

One method is by separation of variables, where you split the equation into two sides and then integrate both sides. Another method is by using an integrating factor, where you multiply the entire equation by a specific function to make it easier to integrate.

4. What is the general form of a second order differential equation?

The general form of a second order differential equation is d2y/dx2 + p(x)dy/dx + q(x)y = g(x), where p(x), q(x), and g(x) are functions of x.

5. How do you solve a second order differential equation?

One method is by using the method of undetermined coefficients, where you assume a solution and then plug it into the equation to solve for the unknown coefficients. Another method is by using the method of variation of parameters, where you assume a general solution and then use a variation of the dependent variable to solve for the unknown coefficients.

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