- #1
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I am reading Anderson and Feil - A First Course in Abstract Algebra.
I am currently focused on Ch. 44: Finite Extensions and Constructibility Revisited ... ...
I need some help in fully understanding Example 44.2 ... ...Example 44.2 reads as follows:
I am trying to fully understand EXACTLY why
##\{ 1, \sqrt{2}, \sqrt{3}, \sqrt{6} \}##
is the basis chosen for ##\mathbb{Q} ( \sqrt{2}, \sqrt{3} )## ... ... I can see why ##1, \sqrt{2}, \sqrt{3}## are in the basis ... and I understand that we need ##4## elements in the basis ...
... BUT ... why EXACTLY do we add ##\sqrt{6} = \sqrt{2} \cdot \sqrt{3}## ... an element that is already in the set generated by ##1, \sqrt{2}, \sqrt{3}## ...
... indeed, what is the rigorous justification for adding ##\sqrt{6}## ... why not add some other element ... ... for example, why not add ##\sqrt{12}## ... Hope someone can help ...
Peter
I am currently focused on Ch. 44: Finite Extensions and Constructibility Revisited ... ...
I need some help in fully understanding Example 44.2 ... ...Example 44.2 reads as follows:
##\{ 1, \sqrt{2}, \sqrt{3}, \sqrt{6} \}##
is the basis chosen for ##\mathbb{Q} ( \sqrt{2}, \sqrt{3} )## ... ... I can see why ##1, \sqrt{2}, \sqrt{3}## are in the basis ... and I understand that we need ##4## elements in the basis ...
... BUT ... why EXACTLY do we add ##\sqrt{6} = \sqrt{2} \cdot \sqrt{3}## ... an element that is already in the set generated by ##1, \sqrt{2}, \sqrt{3}## ...
... indeed, what is the rigorous justification for adding ##\sqrt{6}## ... why not add some other element ... ... for example, why not add ##\sqrt{12}## ... Hope someone can help ...
Peter