- #1
kiro484
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Homework Statement
We completed a lab with the following information
Substance Mass(g) Starting temperature (°C) Final Temperature (°C)
Ice cube 15.55 0 12
Water 151.25 21 12
Now we need to find the specific latent heat of fusion of water
Homework Equations
Q=mcΔt
Q=mH or Q=mL
The Attempt at a Solution
Heat Loss(water)=Heat Gain(ice cube)
mcΔt(water)=mH+mcΔt(ice cube)
Solving for H
H=mcΔt (water)
m+mcΔt (ice cube)
H=(151.25)(4.2)(9)
15.55+15.55(4.2)12
H=5717.25
799.27
This gives me an answer which is nowhere near the actual value of the specific latent heat of fusion of water.
Any help would be greatly appreciated, thanks in advance