One component of mg is mgcosθ. What is the other component of mg along the inclined plane? Similarly find Fcosθ and Fsinθ. Identify their directions.GhostlyKiss said:How do I resolve the horizontal force? Is Fn=mgcos[tex]\oslash[/tex] an equation I would use?
The magnitude of a horizontal force is the numerical value of the force, without any direction. It represents the strength of the force applied in a horizontal direction.
The magnitude of a horizontal force can be calculated using the formula F = ma, where F is the force, m is the mass of the object, and a is the acceleration in the horizontal direction.
The units used to measure magnitude depend on the system of units being used. In the International System of Units (SI), the unit of force is the Newton (N), while in the British system, the unit of force is the pound (lbf).
Magnitude and direction are two different properties of a force. Magnitude refers to the strength of the force, while direction refers to the line along which the force is acting. Both magnitude and direction are needed to fully describe a force.
The magnitude of a horizontal force can be affected by factors such as the mass of the object, the angle at which the force is applied, and any other external forces acting on the object. Friction can also affect the magnitude of a horizontal force by reducing its strength.