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Akash47
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Homework Statement
A layer of liquid with density ##800~kg/m^3## floats on top of a volume of water. A block floats at the oil-water interface with ##3/4## of it in water and the rest of it in the liquid. What is the density of the block?
Homework Equations
Buoyancy =##vρg## where ##v##= volume of the block, ##ρ##=density of liquid, ##g##=gravitational acceleration.
The Attempt at a Solution
(maybe the solution)The block has displaced water of volume of ##3/4## times the block's volume, so buoyancy on it by water is ##3/4~vρ_wg## (##ρ_w##=density of water) which is acting upward.The block has displaced liquid of volume of ##1/4## times the block's volume,so buoyancy acting on it by the liquid is ##1/4~vρ_lg## (##ρ_l##=density of the upper liquid) which is acting upward.We assume downward as negative and upward as positive.The weight of the block is ##vρ_bg## where ##ρ_b##=density of the block.The block is in stating equilibrium,so
##3/4~vρ_wg+1/4~vρ_lg=vρ_bg## implies, ##3/4~v*1000*9.8~+1/4v*800*9.8= vρ_b*9.8##
So, ##ρ_b=950##.
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