- #1
jaejoon89
- 195
- 0
Find the equations for a line that is perpendicular to both of the following lines
x/3 = y/2 = z/2
x/5 = y/3 = (z-4)/2
---
cross product:
<3,2,2> x <5,3,2> = <-2,4,-1>
then the line is
(x-a)/2 = (b-y)/4 = (z-c)/1
but the answer is supposed to be
(1/2)x - (52/7) = (-1/4)y + (52/21) = z - (208/21)
How on Earth do I get that?
x/3 = y/2 = z/2
x/5 = y/3 = (z-4)/2
---
cross product:
<3,2,2> x <5,3,2> = <-2,4,-1>
then the line is
(x-a)/2 = (b-y)/4 = (z-c)/1
but the answer is supposed to be
(1/2)x - (52/7) = (-1/4)y + (52/21) = z - (208/21)
How on Earth do I get that?