- #1
asz304
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Homework Statement
a)f(x) = sqrt(3 + x^2) - 3 x, text( ) text( ) [4, 6] [Find the max. and min. values]
b)y = (3 - x)/(x^2 + 9 x), [2, 7]
The Attempt at a Solution
a)I know how to get the max. and min. value, but before knowing them I need to know how to get the critical points from f(x). The derivative of f(x) is 2x/(sqrt(2+x^2) - 3. I don't know how to get critical points when dealing with fractions.b) I know the derivative of y, then again I don't know how to get critical points when dealing with fractions.
EDIT: In y = x^2 – 6x – 4, [-4, 0], why is the minimum -4 and not -13?
-13 is from the critical point 3, -4 is from the interval 0.
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