Finding atomic magnetic moments

[Bark]

Homework Statement

Calculate atomic magnetic moment of Ni in Bohr magneton.

Given that atomic weight is 58.69, density is 8.91 g/cm^3

Atoms/moments are fully aligned in the field direction and have magnetization of 4.84 x 10^5 A/m

Homework Equations

The Attempt at a Solution

So I have in my notes, if all moments M = Nm, where N = number of dipoles per unit volume, so m = M/N

N is where I m not sure about. If I were finding the mass, I would go 58.69 / 6.02x10^23, then divide density by the mass. From there I would just sub in and find m.

But I m getting a very large number, how do I get from this number to Bohr magneton?

 

[mark726]

To calculate the atomic magnetic moment of Ni in Bohr magneton, we can use the following formula:

μ = (m/V) / (N/V) x M

where μ is the magnetic moment, m is the mass of the atom, V is the volume of the atom, N is the number of dipoles per unit volume, and M is the magnetization.

To find the mass of the atom, we can use the atomic weight given (58.69) and divide it by Avogadro's number (6.02x10^23) to get the mass per atom. Then, we can use the density given (8.91 g/cm^3) to calculate the volume of the atom. Once we have the mass and volume, we can find the number of dipoles per unit volume by dividing the number of atoms by the volume.

Then, we can simply plug in these values into the formula to calculate the atomic magnetic moment in Bohr magneton. I hope this helps. Let me know if you have any further questions.