- #1
SmellyGoomba
- 2
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Homework Statement
Find an equation of the plane that has y-intercept -5 and is parallel to the plane containing the points P(3, -1, 2), Q(0, 2, 1) and R(5, 2, 0)
Homework Equations
ax + by + cz + d = 0
The Attempt at a Solution
I got two directional vectors
u = PQ = (-3, 3, -1)
v = PR = (2, 3, -2)
n = u x v = (-3, -8, -15) which is also equal to (3, 8, 15) because it's a nonzero multiple of n
So putting P and the norm together, I get
3(x-3) + 8(y+1) + 15(z-2) = 0
3x + 8y + 15z - 31 = 0
Now I'm stuck. I have no idea what to do with y-intercept of -5. A push in the right direction would be nice.