- #1
hazellaw
- 2
- 0
how to find two vectors that make an angle of 60O with v=<3,4>??
can i let b=<x,y>, then
cos60=(3x+4y)/5sqrt(x2+y2)
5sqrt(x2+y2)=3x+4y
can i let b=<x,y>, then
cos60=(3x+4y)/5sqrt(x2+y2)
5sqrt(x2+y2)=3x+4y
hazellaw said:how to find two vectors that make an angle of 60O with v=<3,4>??
can i let b=<x,y>, then
cos60=(3x+4y)/5sqrt(x2+y2)
5sqrt(x2+y2)=3x+4y
The formula for finding the angle between two vectors is: cosθ = (a · b) / (|a| * |b|), where a and b are the two vectors and θ is the angle between them.
The magnitude (or length) of a vector can be found by using the Pythagorean theorem, where the magnitude is the square root of the sum of the squares of the vector's components. In this case, the magnitude of vector v = <3,4> is √(3² + 4²) = √25 = 5.
A 60° angle is significant in vector mathematics because it is considered a special angle that can be easily calculated using trigonometric functions. It is also the angle at which the cosine function has a value of 0.5, making it a commonly used angle in various calculations.
To find a vector that makes a 60° angle with a given vector, you can use the formula for finding the angle between two vectors and solve for one of the vectors. In this case, the vector that makes a 60° angle with v = <3,4> would be <5,3> or <5,-3>, as long as the magnitudes of the two vectors are the same.
No, not all pairs of vectors can create a 60° angle. The two vectors must have equal magnitudes and the angle between them must be 60°. Additionally, the dot product of the two vectors must be positive, meaning the two vectors are pointing in the same general direction.