- #1
blueyellow
Homework Statement
find the minimum value taken by the integral expression
integral from 0 to pi/2 [(y')^2]-(y^2)+2xy dx
y(0)=0
y(pi/2)=pi/2
The Attempt at a Solution
using euler lagrange
d/dx(2y')-(-2y+2x)=0
2y''+2y-2x=0
from here I'm stuck