I assume you want to know why the answer to question 3 is incorrect.isukatphysics69 said:
Yes, but you have given too many significant digits in the answer.isukatphysics69 said:
It looks right to me. I got the same answer independently.isukatphysics69 said:
i just tried 3.2m/s incorrecttnich said:
I think we forgot about gravitational potential energy.isukatphysics69 said:
my book says ΔKE = KFINAL - KINITIAL = WA+WGtnich said:
I don't know what WA and WG represent.isukatphysics69 said:
youre righttnich said:
So you need to add up the potential energy (due to gravity and the spring) and kinetic energy. Do this at both the point where the block hits the spring and where it bottoms out.tnich said:
OK, you have all of the pieces. Now you need to write your conservation of energy equation.isukatphysics69 said:
Yes. That's what I got, too.isukatphysics69 said:
The equation used to find the initial speed of a block before it hits a spring is v = √(kx2/m), where v is the initial speed, k is the spring constant, x is the distance the spring is compressed, and m is the mass of the block.
The distance the spring is compressed can be measured by using a ruler or a measuring tape to determine the difference in length between the spring when it is at rest and when it is compressed by the block.
The mass of the block is significant because it affects the amount of potential energy stored in the spring. This potential energy is converted into kinetic energy as the block is released, determining the initial speed of the block.
This equation can be used for any type of spring as long as the spring constant and distance the spring is compressed are known. However, it is important to note that this equation assumes the spring is linear and obeys Hooke's law.
Other factors that may affect the initial speed of the block before it hits a spring include air resistance, friction between the block and the surface it is sliding on, and the angle at which the block is released. These factors may cause the initial speed to be slightly different from the calculated value using the given equation.
