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Find the equation of the tangent line pt 3 (Need someone to check my work)

shamieh

Active member
Sep 13, 2013
539
find the equation of the tangent line.


\(\displaystyle y = e^{3x + cos x}\) @ x = 0

\(\displaystyle
y1 = e^{3(0) + cos(0)} = e^1 = e\)
\(\displaystyle y1 = e\)

\(\displaystyle y = e^{3x+cos x}\)
\(\displaystyle y' = e^{3x + cos x} * (3 - sinx)\)

\(\displaystyle m = 3e\)

\(\displaystyle
y - e = 3e(x - 0) \)
 

topsquark

Well-known member
MHB Math Helper
Aug 30, 2012
1,135
find the equation of the tangent line.


\(\displaystyle y = e^{3x + cos x}\) @ x = 0

\(\displaystyle
y1 = e^{3(0) + cos(0)} = e^1 = e\)
\(\displaystyle y1 = e\)

\(\displaystyle y = e^{3x+cos x}\)
\(\displaystyle y' = e^{3x + cos x} * (3 - sinx)\)

\(\displaystyle m = 3e\)

\(\displaystyle
y - e = 3e(x - 0) \)
Looks good to me!

-Dan
 

shamieh

Active member
Sep 13, 2013
539
Thank God! Was so worried about the \(\displaystyle e^1 = e \)