- Thread starter
- #1

\(\displaystyle y = e^{3x + cos x}\) @ x = 0

\(\displaystyle

y1 = e^{3(0) + cos(0)} = e^1 = e\)

\(\displaystyle y1 = e\)

\(\displaystyle y = e^{3x+cos x}\)

\(\displaystyle y' = e^{3x + cos x} * (3 - sinx)\)

\(\displaystyle m = 3e\)

\(\displaystyle

y - e = 3e(x - 0) \)