# Find the equation of the tangent line pt 3 (Need someone to check my work)

#### shamieh

##### Active member
find the equation of the tangent line.

$$\displaystyle y = e^{3x + cos x}$$ @ x = 0

$$\displaystyle y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$\displaystyle y1 = e$$

$$\displaystyle y = e^{3x+cos x}$$
$$\displaystyle y' = e^{3x + cos x} * (3 - sinx)$$

$$\displaystyle m = 3e$$

$$\displaystyle y - e = 3e(x - 0)$$

#### topsquark

##### Well-known member
MHB Math Helper
find the equation of the tangent line.

$$\displaystyle y = e^{3x + cos x}$$ @ x = 0

$$\displaystyle y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$\displaystyle y1 = e$$

$$\displaystyle y = e^{3x+cos x}$$
$$\displaystyle y' = e^{3x + cos x} * (3 - sinx)$$

$$\displaystyle m = 3e$$

$$\displaystyle y - e = 3e(x - 0)$$
Looks good to me!

-Dan

#### shamieh

##### Active member
Thank God! Was so worried about the $$\displaystyle e^1 = e$$