Find the equation of the tangent line pt 3 (Need someone to check my work)

[shamieh]

find the equation of the tangent line.


\(\displaystyle y = e^{3x + cos x}\) @ x = 0

\(\displaystyle
y1 = e^{3(0) + cos(0)} = e^1 = e\)
\(\displaystyle y1 = e\)

\(\displaystyle y = e^{3x+cos x}\)
\(\displaystyle y' = e^{3x + cos x} * (3 - sinx)\)

\(\displaystyle m = 3e\)

\(\displaystyle
y - e = 3e(x - 0) \)

 

[topsquark]

find the equation of the tangent line.


\(\displaystyle y = e^{3x + cos x}\) @ x = 0

\(\displaystyle
y1 = e^{3(0) + cos(0)} = e^1 = e\)
\(\displaystyle y1 = e\)

\(\displaystyle y = e^{3x+cos x}\)
\(\displaystyle y' = e^{3x + cos x} * (3 - sinx)\)

\(\displaystyle m = 3e\)

\(\displaystyle
y - e = 3e(x - 0) \)

Looks good to me!

-Dan

 

[shamieh]

Thank God! Was so worried about the \(\displaystyle e^1 = e \)