- #1
Yes, but the form of your second relevant equation in your last line of calculations is not. Fortunately you did the actual calculation correctly anywaysFatima Hasan said:Homework Statement
View attachment 223345
Homework Equations
##V= \frac {kq}{r}##
##V= \frac {U}{q}##
The Attempt at a Solution
##V= \frac {kq}{r}## = 9*109*-5*10-9 /0.1= -450 V
##U= \frac {V}{q}## = -450 * -2*10-9 = 900nJ
Is my answer correct ?
Electric potential energy is the energy stored in an object due to its position or configuration in an electric field. It is the potential for an object to do work in an electric field.
Electric potential energy is calculated by multiplying the charge of an object by the electric potential difference (voltage) between two points. The formula for electric potential energy is U = qV, where U is the potential energy, q is the charge, and V is the voltage.
The unit of measurement for electric potential energy is joules (J). This is the same unit used to measure other forms of energy such as kinetic energy and gravitational potential energy.
Electric potential energy and electric potential are closely related. Electric potential is the amount of potential energy per unit charge at a given point in an electric field. In other words, it is the electric potential energy divided by the charge of the object.
The main factors that affect electric potential energy are the distance between charged objects and the amount of charge on those objects. As the distance between charged objects increases, the electric potential energy decreases. As the amount of charge on the objects increases, the electric potential energy also increases.