- #1
cosmictide
- 37
- 0
Hi guys,
This has caused me some confusion. Any help in this regard would be greatly appreciated.
Given that [itex]\theta[/itex] is an acute angle with sin[itex]\theta[/itex]=19/51 find the exact value of cos[itex]\theta[/itex]
All I seem to be getting based on my calculations are approximations. I have no idea how to actually obtain the exact value. Initially I took the inverse of sin[itex]\theta[/itex] to get [itex]\theta[/itex]=21.872...degree. Therefore the cos[itex]\theta[/itex]=0.928...I also tried using a right-angled triangle and finding the adjacent which I calculated to be 47.328... and dividing adj by hyp to see whether I get an exact value but got the same answer as before.
Any help in this regard would be greatly appreciated.
Thanks in advance.
This has caused me some confusion. Any help in this regard would be greatly appreciated.
Homework Statement
Given that [itex]\theta[/itex] is an acute angle with sin[itex]\theta[/itex]=19/51 find the exact value of cos[itex]\theta[/itex]
Homework Equations
The Attempt at a Solution
All I seem to be getting based on my calculations are approximations. I have no idea how to actually obtain the exact value. Initially I took the inverse of sin[itex]\theta[/itex] to get [itex]\theta[/itex]=21.872...degree. Therefore the cos[itex]\theta[/itex]=0.928...I also tried using a right-angled triangle and finding the adjacent which I calculated to be 47.328... and dividing adj by hyp to see whether I get an exact value but got the same answer as before.
Any help in this regard would be greatly appreciated.
Thanks in advance.