Find area of surface obtained by rotating the curve, ?

In summary, the conversation is about using Simpson's rule with n=10 to find the area of a surface obtained by rotating the curve y=x+sqrt(x), 1<=x<=2, about the x-axis. The person is having trouble with their calculations and is seeking help.
  • #1
ani9890
11
0
Find area of surface obtained by rotating the curve, URGENT?

Using Simpson's rule n=10, find the area of the surface obtained by rotating the curve
y=x+sqrt(x), 1 less than or equal to x less than or equal to 2, about the x-axis.
Include at least five decimal places in your answer.
Area = ?

I got:

S = = 2π ∫ (x + √x)√[2 + 1/√x + 1/(4x)] dx (from x=1 to 2).
∆x = (2 - 1)/10 = 1/10.
S ≈ (2π)(1/3)(1/10){g(1) + 4g[1 + 1(1/10)] + 2g[1 + 2(1/10)] + 4g[1 + 3(1/10)] + 2g[1 + 4(1/10)] + 4g[1 + 5(1/10)] + 2g[1 + 6(1/10)] + 4g[1 + 7(1/10)] + 2g[1 + 8(1/10)] + 4g[1 + 9(1/10)] + g(2)}
≈ (π/15)[(1 + 1)√(2 + 1 + 1/4) + 4(20.653233395588) + 2(20.119929259013) + (2 + √2)√(2 + 1/√2 + 1/8)]
≈ 27.68876.

But this is wrong. Please help!
 
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  • #2


ani9890 said:
Using Simpson's rule n=10, find the area of the surface obtained by rotating the curve
y=x+sqrt(x), 1 less than or equal to x less than or equal to 2, about the x-axis.
Include at least five decimal places in your answer.
Area = ?

I got:

S = = 2π ∫ (x + √x)√[2 + 1/√x + 1/(4x)] dx (from x=1 to 2).
∆x = (2 - 1)/10 = 1/10.
S ≈ (2π)(1/3)(1/10){g(1) + 4g[1 + 1(1/10)] + 2g[1 + 2(1/10)] + 4g[1 + 3(1/10)] + 2g[1 + 4(1/10)] + 4g[1 + 5(1/10)] + 2g[1 + 6(1/10)] + 4g[1 + 7(1/10)] + 2g[1 + 8(1/10)] + 4g[1 + 9(1/10)] + g(2)}
Why do you have the factor of 1/3 at the beginning of your calculation?
I don't think that should be there.

In your calculations for g(1), g(1.1), etc. does g(x) = (x + √x)√[2 + 1/√x + 1/(4x)]? You didn't say what g was, so I thought I would check.

I don't see anything wrong - your integral is set up correctly and your Simpson's work looks fine, so it would be worthwhile to doublecheck your calculations. The function you're evaluating is pretty complicated, and it would be easy to get incorrect values.

How are you determining that your answer is incorrect? Are you given the answer or is some computer program saying your answer is wrong? I would compare my results to those obtained from wolframalpha and see how close I got.
ani9890 said:
≈ (π/15)[(1 + 1)√(2 + 1 + 1/4) + 4(20.653233395588) + 2(20.119929259013) + (2 + √2)√(2 + 1/√2 + 1/8)]
≈ 27.68876.

But this is wrong. Please help!
 

Related to Find area of surface obtained by rotating the curve, ?

1. What is meant by "rotating a curve" when finding the area of a surface?

Rotating a curve refers to the process of taking a two-dimensional curve and rotating it around an axis to create a three-dimensional surface. This is commonly used in geometry and calculus to find the area of a surface.

2. How is the area of a surface obtained by rotating a curve calculated?

The area of a surface obtained by rotating a curve can be calculated using a mathematical formula known as the disk or washer method. This involves breaking the surface into infinitesimally thin disks or washers and summing their areas using integration.

3. Can any curve be rotated to find the area of its surface?

Yes, any curve can be rotated around an axis to create a three-dimensional surface. However, the shape and complexity of the resulting surface will vary depending on the shape and properties of the original curve.

4. Are there any real-life applications of finding the area of a surface obtained by rotating a curve?

Yes, there are several real-life applications of this concept, including calculating the volume of objects such as cylinders, cones, and spheres. It is also used in engineering and architecture to determine the surface area of objects like pipes and tanks.

5. Are there any limitations to using the disk or washer method to find the area of a surface?

One limitation of the disk or washer method is that it can only be used for surfaces that can be broken down into simple shapes, such as circles, rectangles, and triangles. This method also requires knowledge of calculus and integration, making it more complex than other methods like the shell method.

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