- #1
Pouyan
- 103
- 8
What will be the final temperature of 3.00 kg of crushed ice with temperature -3.0 C mixed with 4 liters of water with temperature 10.0 C? We can ignore all the energy exchange with the environment
What I do know and I do:
the weight of the ice = 3 kg
Ice temprature = -3 C
melting energy = 3 kg * 333 000 J / kg = 999000 J
weight of water = 4 kg
specific heat capacity of water = 4.2 Jk / kg K
specific heat capacity of ice = 2200 Jk / kg K
I understand just melting energy, but I do not know how will I find out the final temperature. A solution that I have but do not understand why :
dQ ice = 3 * 2200 * (0 + 3) = 19800 J
dQ water = 4 * 4200 * 10 = 168000 J
Melting energy = 999000 JEnd temperature becomes equal to 0. but how can I find it?!
What I do know and I do:
the weight of the ice = 3 kg
Ice temprature = -3 C
melting energy = 3 kg * 333 000 J / kg = 999000 J
weight of water = 4 kg
specific heat capacity of water = 4.2 Jk / kg K
specific heat capacity of ice = 2200 Jk / kg K
I understand just melting energy, but I do not know how will I find out the final temperature. A solution that I have but do not understand why :
dQ ice = 3 * 2200 * (0 + 3) = 19800 J
dQ water = 4 * 4200 * 10 = 168000 J
Melting energy = 999000 JEnd temperature becomes equal to 0. but how can I find it?!
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