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Factoring over the Integers


New member
Apr 16, 2013
try to determine all the positive values of k for which x^2 + 12x + k is factorable over the integers.


Indicium Physicus
Staff member
Jan 26, 2012
Here's my solution:

Set $x^{2}+12x+k=(x+a)(x+b)=x^{2}+(a+b)x+k.$
Evidently, then, the values of $k$ are products of numbers whose sum is $12$. The possibilities are as follows:
1+11=12& \to k=11\\
2+10=12& \to k=20\\
3+9=12& \to k=27\\
4+8=12& \to k=32\\
5+7=12& \to k=35\\
6+6=12& \to k=36.
Then they repeat.