- #1
eigenmax
- 58
- 12
My question regards the polarities of the excitation supply and terminal in an external-excitation VDG.
As you all probably know, external excitation VDGs use a voltage supply (usually 5,000-10,000V) to influence the charge on the lower pulley, instead of just relying on frictional contact to remove electrons from the belt.
My question is, if I place the positive of my supply at the lower pulley, will the positive electrode of the supply draw electrons to it from the belt (as a positive object is an electron deficient one), thereby making a electron-deficient belt and a positive top terminal?
If I use the negative electrode will I have a negative terminal?
There is a little diagram of the excitation supply at the top right.
As you all probably know, external excitation VDGs use a voltage supply (usually 5,000-10,000V) to influence the charge on the lower pulley, instead of just relying on frictional contact to remove electrons from the belt.
My question is, if I place the positive of my supply at the lower pulley, will the positive electrode of the supply draw electrons to it from the belt (as a positive object is an electron deficient one), thereby making a electron-deficient belt and a positive top terminal?
If I use the negative electrode will I have a negative terminal?
There is a little diagram of the excitation supply at the top right.