Exponential and Logarithmic Problem

JoeC

New member
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)

Ackbach

Indicium Physicus
Staff member
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)
What have you tried? Where are you stuck?

JoeC

New member
I don't really know where to start with this.

- - - Updated - - -

the answer to the question is -4/5 but I haven't been able to get it using log or ln.

Klaas van Aarsen

MHB Seeker
Staff member
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)
I don't really know where to start with this.

- - - Updated - - -

the answer to the question is -4/5 but I haven't been able to get it using log or ln.
Welcome to MHB, JoeC!

You have
$$2^x=16(8^{2x})$$
(Or at least that is what I assume you have.)

Since we have $2^x$, let's try to make the other power also a power of $2$.
We have that $8=2^3$.
Do you know what $(2^3)^{2x}$ is?