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Exponential and Logarithmic Problem

JoeC

New member
Jan 27, 2014
2
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)
 

Ackbach

Indicium Physicus
Staff member
Jan 26, 2012
4,197
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)
What have you tried? Where are you stuck?
 

JoeC

New member
Jan 27, 2014
2
I don't really know where to start with this.

- - - Updated - - -

the answer to the question is -4/5 but I haven't been able to get it using log or ln.
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,869
I am looking for help solving for x for the question below. Any help would be greatly appreciated.

2^x=16(8^2x)
I don't really know where to start with this.

- - - Updated - - -

the answer to the question is -4/5 but I haven't been able to get it using log or ln.
Welcome to MHB, JoeC! :)

You have
$$2^x=16(8^{2x})$$
(Or at least that is what I assume you have.)

Since we have $2^x$, let's try to make the other power also a power of $2$.
We have that $8=2^3$.
Do you know what $(2^3)^{2x}$ is?