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- #1

^{2 }= (c - y)

^{2 }+ h

^{2 }I have been previously advised by another member here that;

(c - y)

^{2 }does not equate to c

^{2}- y

^{2 }

OK with this in mind,

a

^{2 }= c

^{2}- 2cy

OK one step at a time.

I squared the C by using 2 outside the bracket, then I moved the 2 inside the bracket and this removed the brackets.

I am assuming that bringing the 2 down I am now subtracting c from C

^{2}thus leaving -2cy.

Is this the case I am not sure?

Then it seems the y

^{2 }is then added back.

I originally had (c - y)

^{2}

I seem to have ended up with more than I started with?

Could somebody please explain it?

Kind regards

Casio