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unique_pavadrin
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URGENT: Integrate exactly
Using the substitution [tex]x = \sec ^2 u[/tex], evaluate [tex]\int_2^4 {\frac{{dx}}{{x^2 \sqrt {x - 1} }}} [/tex] exactly
2. The attempt at a solution
I have used the substitution and ended up with (after some simplification)
[tex]\int_2^4 { - 2\cos ^2 u.\sin u.\sqrt {\sec ^2 u - 1} }[/tex]. What do i do now? How do I integrate that, I am very confused on how to go about this now. There are others which I need to solve, but are harder than this one, so I will post them in the future once i understand this one and if i still need help with them. Many thanks to those who help
unique_pavadrin
Homework Statement
Using the substitution [tex]x = \sec ^2 u[/tex], evaluate [tex]\int_2^4 {\frac{{dx}}{{x^2 \sqrt {x - 1} }}} [/tex] exactly
2. The attempt at a solution
I have used the substitution and ended up with (after some simplification)
[tex]\int_2^4 { - 2\cos ^2 u.\sin u.\sqrt {\sec ^2 u - 1} }[/tex]. What do i do now? How do I integrate that, I am very confused on how to go about this now. There are others which I need to solve, but are harder than this one, so I will post them in the future once i understand this one and if i still need help with them. Many thanks to those who help
unique_pavadrin