- #1
GreenLantern
- 30
- 0
what'd I do wrong?
I was told I didn't include the bound y<=x but that still hasn't helped me figure out where I miss stepped
thanks
-Ben
Last edited:
To convert a double integral to polar coordinates, you need to substitute the variables x and y with their polar coordinate equivalents: x = rcosθ and y = rsinθ. You also need to replace the dx dy term with r dr dθ. Remember to adjust the limits of integration accordingly.
Polar coordinates are useful for evaluating integrals that have circular or radial symmetry. This can make the integral easier to solve, as the boundaries of the region of integration may be simpler to define in polar coordinates.
Using polar coordinates can simplify the integrand and make it easier to evaluate, especially for integrals with circular or radial symmetry. It can also help to reduce the number of variables and parameters in the integral.
The new limits of integration in polar coordinates will depend on the shape and boundaries of the region of integration. To determine the limits, you can draw a diagram and use geometric reasoning to find the relationships between the rectangular and polar coordinates. You can also use trigonometric identities to express the limits in terms of θ.
No, not all double integrals can be converted to polar coordinates. The integral must have circular or radial symmetry in order for the conversion to be valid. Additionally, the region of integration must be more easily defined in polar coordinates.