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- Feb 14, 2012
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Given the system of equation below:
$a + 2b + 3c + 4d = 262$
$4a + b + 2c + 3d = 123$
$3a + 4b + c + 2d = 108$
$2a + 3b + 4c + d = 137$
Evaluate $27a+ 28b + 29c + 30d$.
$a + 2b + 3c + 4d = 262$
$4a + b + 2c + 3d = 123$
$3a + 4b + c + 2d = 108$
$2a + 3b + 4c + d = 137$
Evaluate $27a+ 28b + 29c + 30d$.