- #1
barbiegirl42
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Homework Statement
A 60 kg tight-rope walker carries a long beam with
a mass of 30 kg across a 10 m long wire. When
she is at the centre of the wire (i.e. 5 m across),
each section of the wire makes an angle of 5° to
the horizontal. Assuming that the mass of the wire
is negligible, calculate the tension within it.
I would like to know if my process is right. I took forever just trying to figure out the problem and would like to verify that my process is correct or if there any omissions I may have left out.
Homework Equations
T=rf
Sum of the forces = 0
Sin=0 / H
The Attempt at a Solution
Sum of the forces = 0
F(Tightrope walker) + F(Beam) = F(Tension in one half of the rope) + F(Tension in the other half)
(60x9.8) + (30x9.8) = F(T1) + F(T2)
822=F(T1) + F(T2)
882 / (2 x Sin5 x 5)
= 1011.98
1011.98 / 2
= 505.98
= 506 N <~ My answer is right, I checked in the answers section from the book.