- #1
nasadall
- 28
- 0
Thanks.
This next one is a bit confusing, not so much the first part, its the second, i think i got it wright, i just don't know how to put it on peper to present it to the tutor.
b) A car is being driven along a straight and level road at a steady speed of
25 ms-1 when the driver suddenly notices that there is a fallen tree blocking the
road 65 metres ahead. The driver immediately applies the brakes giving the car
a constant retardation of 5 ms-2.
i) How far in front of the tree does the car come to a halt?
u=25 m/s v=0 m/s a=-5 m/s2 s=?
so using v2=u2+2as
my result was
02=252+2(-5)s
0=625+(-10)s
10s=-0-625
s=-625/-10
s=62.5
then i take away the 62.5 meters treveled while deccelerating, from the 65 meters from where the tree was spoted.
65-62.5 = 2.5 meters that the car came to a halt in front of the tree.
This next one is a bit confusing, not so much the first part, its the second, i think i got it wright, i just don't know how to put it on peper to present it to the tutor.
b) A car is being driven along a straight and level road at a steady speed of
25 ms-1 when the driver suddenly notices that there is a fallen tree blocking the
road 65 metres ahead. The driver immediately applies the brakes giving the car
a constant retardation of 5 ms-2.
i) How far in front of the tree does the car come to a halt?
u=25 m/s v=0 m/s a=-5 m/s2 s=?
so using v2=u2+2as
my result was
02=252+2(-5)s
0=625+(-10)s
10s=-0-625
s=-625/-10
s=62.5
then i take away the 62.5 meters treveled while deccelerating, from the 65 meters from where the tree was spoted.
65-62.5 = 2.5 meters that the car came to a halt in front of the tree.