- #1
lampshader
- 39
- 0
Homework Statement
An ordinary 150-Watt light bulb has a resistance of about 96 ohms.
Suppose you were to connect a 2.0 V battery to such a light bulb. How much current would flow? Determine how much power the bulb would radiate? (probably too little for a person to detect). Use you own calculations for this question. The lab can be used to test your results by comparing a similar model.
Homework Equations
I = E (base eq) / R (base eq);
P (base w) = I^2*R.
I don't know the equation to find the power a light bulb would radiate
in a given electrical circuit.
The Attempt at a Solution
If I hooked a 150 W bulb (about 96 Ohms) to a 2V Battery then:
E (base eq) = 2V
R (base eq) = 96 Ohms.
I = E (base eq) / R (base eq) = 2V / 96 Ohms =~ 0.02080A
0.02080 A is the current that a 150 Watt Light Bulb would draw from a 2V Battery.
To find the power that would dissipate:
P (base w) = I^2*R = (0.02080A)^2 * 150 Ohms =~ 0.06514;
is the amount of power dissipated