- #1
omnislash
- 3
- 0
Homework Statement
Four identical light bulbs are connected to a battery as shown in the diagram. Switch S is originally closed. If switch S is opened, what happens to the brightness of each bulb?
Homework Equations
V=IR
The Attempt at a Solution
- By opening the switch, no more current flows through bulb 2
- Therefore, the equivalent resistance of the bulbs in that branch increase
- Current produced by battery decreases, which means the current entering the junction is lower than before
This is where the problem beings:
- I said that bulb 1 would be dimmer since it has less current flowing through it, but it turned out that the brightness never changed
- I said bulb 3 receives less current and has greater equivalent resistance, so the brightness never changed. I was wrong
- I am clueless on bulb 4
Can somebody help me out?
Attachments
Last edited: