- #1
SalfordPhysics
- 69
- 1
Homework Statement
For a nitrogen molecule, calculate the lowest 2 energy levels and the characteristic temperature;
Mass of molecule = 2.33x10-26[kg]
Length of box = 10-9[m]
Homework Equations
E = n2.h2/8mL2 (n=1,2,3,...)
Characteristic Temperature (Tc) -> when thermal energy kBT = energy spacing of lowest 2 levels.
The Attempt at a Solution
[/B]
E1 = h2/(8).(2.33x10-44)
= 2.358x10-24 [J]
E2 = n2.(E1) = 4(E1) = 9.432x10-42
Tc = (E2 - E1)/kB = 7.074x10-24 / kb = 0.512 [Kelvin]
The final answer quite simply does;t seem right to me, but I have checked numerous times my calculations. Can anyone clarify please.