Electric Field Between Two Charged Rings: Problem Solved

In summary, the electric field strength at the midpoint between two 10-cm-diameter charged rings, both charged to +50.0 nC and facing each other 19.0 cm apart, is 0 due to the symmetry of the configuration. The same applies for the electric field at the center of the left ring, which is also 0 due to symmetry. However, the electric field at these points is not zero due to the contribution of the other ring. The formula for the electric field is E = q/4pi*ep_o*r^2, and for this problem, physical intuition can be used to determine the field due to the symmetry of the situation. The field from the ring in its center and the field
  • #1
Linus Pauling
190
0
1. Two 10-cm-diameter charged rings face each other, 19.0 cm apart. Both rings are charged to + 50.0 nC. What is the electric field strength:

At the midpoint between the two rings? At the center of the left ring?




2. E = q/4pi*ep_o*r^2



3. The online problem says this is from a certain chapter in our book... that chapter (which we've read) is about point charges. Am I able to treat these things as point charges? I would think not given the small distances being considered... so think maybe it's a typo. Anyways, could someone outline the strategy for this type of problem?
 
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  • #2
Is the answer zero in both cases? Since they're both positively charged, the field lines will point into the space between the rings, but then curve upwards as they come together since they're the same sign, so the middle is zero? Likewise, the center of one ring is zero because the y component of the field from that ring cancels out?
 
  • #3
The field at the midpoint is 0 because of the symmetry of the configuration. Likewise, the field at the center of a ring due to that ring is 0, again due to symmetry. You still have to consider the electric field produced by the other ring, which isn't 0.
 
  • #4
Well, if I remember, the field at a point is the force experienced by unit charge at the point so they could say point charges come into it, haw haw.

This one is asking for a minimum of physical intuition I guess. The first problem is very symmetrical. As preliminary, a still simpler situation, what is the net result force on a charge just half way between to equal point charges (both of the same sign)?

Moving on to the rings, you can assume the distribution of charge is uniform around the ring. Makes a very symmetrical situation.

In the second problem, the field is (still) the (vector, i.e. directional) sum of the field due to the two different rings. That from the ring it's in the centre of is an extremely symmetrical situation.

3/4 of the question requires no calculation really. :wink:
 
  • #5
2 other posts came in whilst I was typing mine. If you mean to say points equally distant from equal charges the field is zero, agreed.

Agree field from ring in its centre is zero. So that leaves you with only the second part of the second problem.
 

Related to Electric Field Between Two Charged Rings: Problem Solved

1. What is an electric field between two charged rings?

An electric field between two charged rings is a region in space where electrically charged particles experience a force. In this case, the electric field is created by two charged rings, with one ring having a positive charge and the other having a negative charge.

2. How is the electric field between two charged rings calculated?

The electric field between two charged rings can be calculated using the formula E = kQ/r, where E is the electric field strength, k is the Coulomb's constant, Q is the charge of the ring, and r is the distance between the two rings. This formula is derived from Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

3. What factors affect the strength of the electric field between two charged rings?

The strength of the electric field between two charged rings is affected by the magnitude of the charges on the rings, the distance between the rings, and the medium between the rings. The electric field is stronger when the charges are larger, the distance between the rings is smaller, and the medium between the rings has a lower dielectric constant.

4. How does the direction of the electric field between two charged rings change?

The direction of the electric field between two charged rings depends on the relative positions of the two rings. If the rings are aligned along the same axis, the electric field will be directed from the positively charged ring to the negatively charged ring. If the rings are placed at an angle, the electric field will be directed along the line connecting the two rings.

5. What are some real-world applications of the electric field between two charged rings?

The electric field between two charged rings has a variety of practical applications, including in capacitors, electric motors, and particle accelerators. It is also used in medical devices such as MRI machines and defibrillators. Understanding the electric field between charged rings is crucial in designing and optimizing these technologies.

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