- #1
Fiorella
- 17
- 0
Let f be the funtion given by f(x) = 4x^2 - x^3 , let L be the line y = 18 - 3x, where L is tangent to the graph of f.
Show that L is the tangent to the graph of y= f(x) at the point x = 3.
I'm equaling both graphs like this:
4x^2 - x^3 = 18 - 3x
and then I isolate everything to the right:
0 = x^3 - 4x^2 - 3x + 18
But I don't know how to factor this...am I in the right track to prove that this line is tangent to the function?
Show that L is the tangent to the graph of y= f(x) at the point x = 3.
I'm equaling both graphs like this:
4x^2 - x^3 = 18 - 3x
and then I isolate everything to the right:
0 = x^3 - 4x^2 - 3x + 18
But I don't know how to factor this...am I in the right track to prove that this line is tangent to the function?