- #1
tsuria
Homework Statement
Plotted a distance vs time graph for acceleration on an inclined plane (constant acceleration) and got graph equation of y = 10.242x^2 + 25.996x - 10.315
So this means that d = 1/2at^2 + vt - y intercept
Meaning 1/2 acceleration is 10.242 and initial velocity is 25.996 right?
Then I plotted distance vs time squared and got y=18.448x+8.3244 so this means d=1/2at^2 + y intercept right? So the 1/2 acceleration here is 18.448.
Question is why are the two 1/2 accelerations of different values? How do I explain it?