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Niaboc67
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Homework Statement
At 9 P.M. an oil tanker traveling west in the ocean at 18 kilometers per hour passes the same spot as a luxury liner that arrived at the same spot at 8 P.M. while traveling north at 23 kilometers per hour. If the "spot" is represented by the origin, find the location of the oil tanker and the location of the luxury liner t hours after 8 P.M. Then find the distance D between the oil tanker and the luxury liner at that time.
D(t) =
The Attempt at a Solution
T=18(t-1)
L=23t
T=18t-18 km west of the origin
L=23t km north of the origin
d=((18t-18)^2+(23t)^2)^(1/2)
d=(324t^2-648t+324+529t^2)^(1/2)
d=(853t^2-648t+324)^(1/2)
dd/dt=(853t-324)/(853t^2-648t+324)^(1/2...
dd/dt=0 only when 853t=324
t=0.3798h
d(.3798)=
So, here is where I am unsure about the answer
Plugging back into the original sqrt( (18t-18)^2 + (23t)^2 )
d(0.3798) = sqrt( (18(0.3798) - 18)^2 + (23(0.3798))^2 ) = 11.311
Is this what you guys got? I am on my last try on my homework and am very unsure about the work here.
Thank you
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