- #1
fr33pl4gu3
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If one plots the graph of
y = x2-10 x+24
which is a parabola, one observes that it is above the x axis, i.e. y > 0, for two intervals of the real line. (The union of these intervals constitute the set of solutions of the quadratic inequality at the beginning of this question.)
Find the intervals.
How do you do this anyway??
Is it like take x = 3, and put it in and come out with y = 3, the the intervals would be (3,3)
y = x2-10 x+24
which is a parabola, one observes that it is above the x axis, i.e. y > 0, for two intervals of the real line. (The union of these intervals constitute the set of solutions of the quadratic inequality at the beginning of this question.)
Find the intervals.
How do you do this anyway??
Is it like take x = 3, and put it in and come out with y = 3, the the intervals would be (3,3)