- #1
center o bass
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- 2
Homework Statement
Solve
[tex]y''(t) - k^2 y(t) = e^{-a|t|}[/tex] where a and k are both positive and real.
Homework Equations
The solution was obtained trough a Fourier transform.
The Attempt at a Solution
I got the solution
[tex]y(t) = \frac{ke^{-at} - ae^{-kt}}{k(a^2 - k^2)}[/tex]
but when i plug it back into the differential equation i just get
[tex]e^{-at}[/tex]
how could I get the absolute value back in there?
Might there be anything wrong with my solution procedure?