Diff Eq problem, Laplace Transform

In summary, the conversation discusses finding the Laplace Transform of a function involving a heavyside function and using the proposition L{H(t-c)f(t-c)}(s)=e^(-cs)F(s). The final solution is 2e^s/s^3.
  • #1
DF19
6
0

Homework Statement


Find the Laplace Transform of the given function
H(t-1)t^2

I'm not sure how to add (t-1) to the t^2 term to solve the problem

Any help would be greatly appreciated.
 
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  • #2
That notation makes no sense, are you trying to translate the function on the s-axis? If you are what is the original function.
 
  • #3
If the original function is e^t*t^2 the translation = F(s-1) and since f(t)=t^2 its transform is 2/s^3, therefore you substitute s-1 in for s and get 2/(s-1)^3. Unless you are doing an inverse translation on the t-axis.
 
  • #4
My book states that it is a H(t) is a heavyside function and I'm suppose to use the proposition:

L{H(t-c)f(t-c)}(s)=e^(-cs)F(s)
 
  • #5
Oh a unit step therefore you must translate both H(t) and F(t). LH(t-1)=e^s and f(t)=t^2, L(t^2)=2/s^3, so the transform is 2e^s/s^3
 

Related to Diff Eq problem, Laplace Transform

What is a differential equation?

A differential equation is a mathematical equation that describes the relationship between an unknown function and its derivatives. It involves expressing the rate of change of a system's variables in terms of the variables themselves.

What is the Laplace transform?

The Laplace transform is a mathematical tool that converts a function of time into a function of complex frequency. It is commonly used to solve differential equations, as it transforms a differential equation into an algebraic equation, which is often easier to solve.

How is the Laplace transform used to solve differential equations?

The Laplace transform is used to solve differential equations by transforming the equation into an algebraic equation, which can then be solved using algebraic methods. Once the solution is found, the inverse Laplace transform is used to convert the solution back into the original function of time.

What are the advantages of using Laplace transform to solve differential equations?

The advantages of using Laplace transform to solve differential equations include its ability to handle initial conditions, its efficiency in solving linear differential equations, and its usefulness in solving integral and differential equations with variable coefficients.

Are there any limitations to using Laplace transform to solve differential equations?

One limitation of using Laplace transform to solve differential equations is that it may not work for all types of differential equations. It is also limited in its ability to handle nonlinear differential equations and equations with discontinuous functions. Additionally, it requires knowledge of complex analysis and may involve complex arithmetic, making it more challenging to use than other methods for solving differential equations.

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