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Homework Statement
Find a particular solution of the given equation.
[tex] y^''' + 4y^' = 3x-1[/tex]
Homework Equations
[tex] r^3 + 4r = 0 [/tex]
[tex] r = 0, r = 2i, r = -2i[/tex]
The Attempt at a Solution
[tex]y(x) = Ax-B[/tex]
[tex]y^'(x) = A[/tex]
[tex]y^''(x) = 0[/tex]
[tex]y^'''(x) = 0[/tex]
The answer is:
[tex]y(x)=(3/8)x^2 - (1/4)x[/tex]
But I'm not sure how they came to this, please help!