Diagonalizing Linear Transformations on Finite-Dimensional Real Vector Spaces

In summary, T is diagonalisable if and only if there exists an inner product on V relative to which T is self-adjoint.
  • #1
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"Let T be a linear transformation on a finite dimensional real vector space V. Show that T is diagonalisable if and only if there exists an inner product on V relative to which T is self-adjoint."

The backward direction is easy. As for the forward direction, I don't understand how given an arbitrary vector space, you can go about defining an inner product without knowing something more about it.
 
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  • #2
Although it's not really relevant, your vector space isn't arbitrary, it's isomorphic to Rn for some n. Anyways, you don't have to know anything about V, you just have to be able to define an inner product on it, and an inner product is just a function [itex]\langle .,.\rangle\, :\, V\times V \to \mathbb{R}[/itex] that is symmetric, positive definite, and bilinear (there may be another condition or two, you can look it up). So just define a function that has these properties, and is also such that T is self-adjoint with respect to it.

Now the problem is, how to find an inner product such that T is self-adjoint relative to it. Well what things do you know about T, given that it's diagonalizable? Second, you're not going to write out what <v,w> is for each individual v and w in V. Given that inner products are multilinear, it suffices to define an inner product on a ______. But you should know that if T is diagonalizable, there is a ______ with some strong relation to T. Fill in the blank, figure out what that "strong relation" is, and use it to prove that T is self-adjoint w.r.t. your inner product.
 
  • #3
As for the forward direction, I don't understand how given an arbitrary vector space, you can go about defining an inner product without knowing something more about it.
The only thing there is to know about a (finite-dimensional real) vector space is its dimension.

Anyways, I think the backward direction gives you a strong hint about how to proceed with the forward direction.
 
  • #4
Got it. Thanks.
 

Related to Diagonalizing Linear Transformations on Finite-Dimensional Real Vector Spaces

1. What is the importance of diagonalizing linear transformations?

Diagonalizing linear transformations is important because it simplifies the representation of a linear transformation by breaking it down into its most basic form. This allows for easier analysis and computation of the transformation's properties.

2. How do you diagonalize a linear transformation?

To diagonalize a linear transformation, you must find a basis for the vector space that consists of eigenvectors of the transformation. Then, you can construct a diagonal matrix using the eigenvalues of the transformation as the diagonal entries.

3. Can all linear transformations be diagonalized?

No, not all linear transformations can be diagonalized. Only transformations that have a full set of linearly independent eigenvectors can be diagonalized.

4. What is the significance of the eigenvalues and eigenvectors in diagonalizing linear transformations?

The eigenvalues and eigenvectors of a linear transformation are crucial in diagonalizing because they determine the diagonal entries of the resulting matrix. They also provide information about the behavior of the transformation, such as stretching or contracting along certain directions.

5. How does diagonalization relate to other properties of linear transformations?

Diagonalization is closely related to other properties of linear transformations, such as invertibility and similarity. A diagonalizable transformation is always invertible, and two similar transformations have the same diagonal representation. Additionally, diagonalization can help in finding the Jordan canonical form of a transformation.

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