- #1
Wiccan
- 1
- 0
Dear all,
I'm a bit confused about a 2D problem which I thought had a simple solution...
I don't know if I'm correct, so:
I have a 2D space, and time. I know the velocity field v(x,y,t). I would like to know where the particle which start at the position x0,y0 at an istant t0 is at a certain istant t>t0.My idea is:
p(t)=<px(t),py(t)>
dp/dt=v(p,t)=<vx(px,py,t),vy(px,py,t)>
%%%
dpx/dt=vx(px,py,t)
dpy/dt=vy(px,py,t)
%%%
Then I would solve it by part...even if the solution can be not easy due to dependence on time,
Ex:
vx=px*t, vy=px*py
%%% % %%
dpx/px=t dt %px=c1*exp(0.5*t^2)
dpy/py=px dt %dpy/py=c1*exp(0.5*t^2)dt etc...
%%% %%%
Is this answer formally correct?
I'm a bit confused about a 2D problem which I thought had a simple solution...
I don't know if I'm correct, so:
I have a 2D space, and time. I know the velocity field v(x,y,t). I would like to know where the particle which start at the position x0,y0 at an istant t0 is at a certain istant t>t0.My idea is:
p(t)=<px(t),py(t)>
dp/dt=v(p,t)=<vx(px,py,t),vy(px,py,t)>
%%%
dpx/dt=vx(px,py,t)
dpy/dt=vy(px,py,t)
%%%
Then I would solve it by part...even if the solution can be not easy due to dependence on time,
Ex:
vx=px*t, vy=px*py
%%% % %%
dpx/px=t dt %px=c1*exp(0.5*t^2)
dpy/py=px dt %dpy/py=c1*exp(0.5*t^2)dt etc...
%%% %%%
Is this answer formally correct?