- #1
jdstokes
- 523
- 1
Hi,
I'm curious if the following statement is true for all prime numbers n,
[itex]\det_{\mathbb{Z}_n}M = (\det_{\mathbb{R}}M)\mod n[/itex]
where [itex]\det_F M[/itex] is the determinant of M over the field F.
Thanks.
James
I'm curious if the following statement is true for all prime numbers n,
[itex]\det_{\mathbb{Z}_n}M = (\det_{\mathbb{R}}M)\mod n[/itex]
where [itex]\det_F M[/itex] is the determinant of M over the field F.
Thanks.
James
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