- #1
TommG
- 28
- 0
Need to find derivative
y = θ(sin(ln θ)) + cos(ln θ)
My work
θ(cos(ln θ))(1/θ) + sin(ln θ) + (-sin(ln θ)(1/θ))
(θcos(ln θ))/θ] + sin(ln θ) + ( (- sin(ln θ))/θ)
cos(ln θ) + [θsin(ln θ) - sin(ln θ)]/ θ
answer in book is 2cos(lnθ)
y = θ(sin(ln θ)) + cos(ln θ)
My work
θ(cos(ln θ))(1/θ) + sin(ln θ) + (-sin(ln θ)(1/θ))
(θcos(ln θ))/θ] + sin(ln θ) + ( (- sin(ln θ))/θ)
cos(ln θ) + [θsin(ln θ) - sin(ln θ)]/ θ
answer in book is 2cos(lnθ)