- #1
quark001
- 44
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Find the derivative of y = arctan(x^(1/2)).
Using the fact that the derivative of arctanx = 1/(1+x^2) I got:
dy/dx = 1/(1+abs(x)) * (1/2)x^(-1/2)
But my textbook gives it without the absolute value sign. I don't understand why because surely x^(1/2) squared is the absolute value of x and not simply x?
Using the fact that the derivative of arctanx = 1/(1+x^2) I got:
dy/dx = 1/(1+abs(x)) * (1/2)x^(-1/2)
But my textbook gives it without the absolute value sign. I don't understand why because surely x^(1/2) squared is the absolute value of x and not simply x?