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moatasim23
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According to Debroglie Eq λ=h/mv λ and v inversely proportional to each other.But according to eq v=f*λ they seem to be directly proportional.So what is the actual dependence of lambda on v?
moatasim23 said:According to Debroglie Eq λ=h/mv
v=f*λ
USeptim said:A particle with [precisely] zero momenta by definition it's a plane wave on the spatial representation with zero frequency and therefore infinite wave length.
moatasim23 said:According to Debroglie Eq λ=h/mv λ and v inversely proportional to each other.But according to eq v=f*λ they seem to be directly proportional.So what is the actual dependence of lambda on v?
Yes, the wavelength will be infinite. If the particle has a nonzero rest mass, then the phase velocity will be infinite, too.moatasim23 said:Wt if a paritcle has zero speed in a particular reference frame?Will its wavelenth then be infinite?
The Debroglie Wavelength is a concept in physics that describes the wavelength of a particle, such as an electron, as it behaves like a wave. It is named after physicist Louis Debroglie who first proposed the idea in 1924.
The Debroglie Wavelength is directly proportional to the velocity of the particle. This means that as the velocity of the particle increases, its Debroglie Wavelength also increases.
The formula for calculating the Debroglie Wavelength is λ = h/mv, where λ is the Debroglie Wavelength, h is Planck's constant, m is the mass of the particle, and v is the velocity of the particle.
The Debroglie Wavelength is typically measured in meters (m) or nanometers (nm), depending on the size of the particle.
The Debroglie Wavelength is an important concept in quantum mechanics as it helps to explain the wave-particle duality of matter. It shows that particles, such as electrons, have both wave-like and particle-like properties, and can be described by both classical and quantum mechanics.