- #1
terryds
- 392
- 13
Imagine a ball rolling down a hill or inclined plane without slipping from a particular height.
The conservation of energy law says that the final energy remains the same as the initial energy.
But, when a ball is rolling without slipping, there must be a friction.
So, what I think is
E = E'
mgh + Ffriction s = (1/2) mv^2 + (1/2) Iω^w
But, in every book I read says that
E = E'
mgh = (1/2) mv^2 + (1/2) Iω^w
Why is there no work done by friction ?
I questioned this since if the ball is not rolling, it must be mgh + Ffriction s = (1/2)mv^2
But, when it's rolling, there is no work done by friction.. Why?
The conservation of energy law says that the final energy remains the same as the initial energy.
But, when a ball is rolling without slipping, there must be a friction.
So, what I think is
E = E'
mgh + Ffriction s = (1/2) mv^2 + (1/2) Iω^w
But, in every book I read says that
E = E'
mgh = (1/2) mv^2 + (1/2) Iω^w
Why is there no work done by friction ?
I questioned this since if the ball is not rolling, it must be mgh + Ffriction s = (1/2)mv^2
But, when it's rolling, there is no work done by friction.. Why?