Cost of Fencing for Parking Lot: Function of Width w | Tricky Word Problem

[you_of_eh]

Fencing around a rectangular parking lot costs twice as much along the side facing the street than the other three sides. The fencing along the back of the lot costs $10 per meter. Express the cost C of the fence as a function of the width w if the length of the street side of the parking lot is 20m longer than the width.

Here is the best I could come up with..

C(w)=(3w+2/3w)$10+(w+2/3w)$20

How does that look?

 

[you_of_eh]

2nd attempt..

C(w)=$10/m(5w+60m)

 

[Architeuthis Dux]

my response to this problem would be to first clarify the given information and assumptions. It is stated that the parking lot is rectangular, and the length of the street side is 20m longer than the width. Therefore, we can assume that the length of the street side is (w+20)m and the length of the other three sides is w.

Next, we can define the cost of fencing for the entire parking lot as the sum of the cost for the three regular sides and the cost for the street side. The cost for the three regular sides is (3w+w+w) multiplied by $10, as stated in the problem. Simplifying this expression, we get 5w multiplied by $10, which is equal to $50w.

The cost for the street side is (w+20) multiplied by $20, since it is stated that this side costs twice as much. Simplifying this expression, we get 20w+400.

Therefore, the total cost of fencing, C(w), can be expressed as C(w)=$50w+20w+400, which simplifies to C(w)=$70w+400.

In summary, the cost of fencing for the parking lot can be expressed as a function of the width w, where C(w)=$70w+400. This function can be used to calculate the cost for any given width of the parking lot.