Correcting My Answer: Ensuring Accuracy and Improving Learning

[r-soy]

Hi

I want check my answer and If there any mistake please correct it to me[/b]

 

[Mark44]

The ninth root of -512 is not equal to -56.

 

[r-soy]

what is the mistake ?

 

[Mentallic]

-512 divided by 9 [itex]\approx[/itex] -56 (but not exactly)
But the ninth root is not division.

Anyway, following on from that mistake, when you used the formula:

[tex]\frac{a\left(1-r^n\right)}{1-r}[/tex]

You substituted incorrectly. a=1/4, r=-56 (your mistake), n=5 (since it asks for the 5th term)
This is what you had:
[tex]\frac{\frac{1}{4}\left(1-(-56)^9\right)}{1-(-9)}[/tex]

This is what you should have:
[tex]\frac{\frac{1}{4}\left(1-(-56)^5\right)}{1-(-56)}[/tex]

But anyway, following on from that mistake also, whatever happened to the [itex]1-r^n[/itex] part?

[itex]1-(-56)^9[/itex] all of a sudden became something like 5x4 from the looks of it, but since you end up with the answer of -5.7 from there, it means that part must've been equal to 182.4, but it doesn't seem like it is.

Honestly, you need to go back and revise your algebra. You will struggle to solve all these harder questions if you don't have a firm foundation with algebra.

 

[Mentallic]

Oh and you wrote that the right-hand column is T₁₀. The question says to find the 5th term (T₅) and already gives you [itex]T_{10}=-128[/itex].

 

[Mark44]

You're given that a = -1/4 and T₁₀ = -128, and you need to find the common ratio r.

T₁₀ = ar⁹
==> -128 = (-1/4)r⁹
==> -512 = r⁹
==> [tex]r = \sqrt[9]{-512}[/tex]
As I said in my first post, the 9th root of -512 is not -56. If that were true (which it isn't), it would have to be the case that (-56)⁹ = -512.

By my calculator, (-56)⁹ = -5416169448144896, so that's off by quite a bit. So what is the correct ninth root of -512? Hint: try factoring -512.

 

[r-soy]

Thank D .mark