Coriolis effect, a girl on holding a ball on a carousel

In summary: This radial force is always pointing towards the center of the carrousel. Because the carrousel's velocity is constant, the radial force is also constant. Therefore, the radial component of the force necessary to keep the ball stationary is simply the mass of the ball multiplied by the carrousel's velocity. So the girl would need to apply a force of .3024 N in order to keep the ball stationary. Thanks for your help!In summary, the girl needs to apply a force of .3024 N in order to keep the ball stationary on the moving carousel
  • #1
nothingislost
8
1
A carousel going counter clockwise starts from rest and accelerates at a constant angular acceleration of 0.02 rev/s^2. A girl sitting on a bench on the platform 7 m from the center is holding a 3kg ball. Calculate the magnitude and the direction of the force she must exert to hold the ball 6s after the carousel starts to move. Give the direction with respect to the line from the center of rotation to the girl.

So the moving carousel simply creates an effective force on the ball opposite its rotation. I think the only force is mw^2r, where m is the mass on the ball w is the angular velocity and r is distance from the center of rotation to the girl. Is this right? the direction of the force the girl puts on the ball is opposite the natural force and tangent the the motion. I am getting .3024 N but this seems very small.

thanks
 
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  • #2
Welcome to PF!

Hi nothingislost! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Why bother with Coriolis force etc?

Why not just calculate the acceleration of the ball?

It's being forced to go in a circle of constant radius 7 m, at an angular acceleration of 0.02 rev/s2, so its radial and tangential accelerations are … ? :smile:
 
  • #3
nothingislost said:
A carousel going counter clockwise starts from rest and accelerates at a constant angular acceleration of 0.02 rev/s^2. A girl sitting on a bench on the platform 7 m from the center is holding a 3kg ball. Calculate the magnitude and the direction of the force she must exert to hold the ball 6s after the carousel starts to move. Give the direction with respect to the line from the center of rotation to the girl.

So the moving carousel simply creates an effective force on the ball opposite its rotation. I think the only force is mw^2r, where m is the mass on the ball w is the angular velocity and r is distance from the center of rotation to the girl. Is this right? the direction of the force the girl puts on the ball is opposite the natural force and tangent the the motion. I am getting .3024 N but this seems very small.

thanks

I think you forgot a factor [itex] 2 \pi [/itex] in w

There's also the tangential acceleration. (And there's no coriolis force if the ball doesn't move with respect to te caroussel)
 
  • #4
Hi nothingislost! :smile:

Please always reply on the thread, not by PM.
nothingislost said:
thanks so much for your response and help.

So if we have the tangential acceleration and the centripetal accelerations to find the force the girl would have to apply we would add the two vectors of forces (tangential and centripetal) and then the opposite of this result would give us the force, is this right?

No

the force is always parallel to the acceleration, not opposite to it.

(are you being confused by "centrifugal force"? if so, just remember that centrifugal force is imaginary … only centripetal forces are real)
 
  • #5
ok i see and the total force necessary would just be the tangential and the centripetal forces, basically somewhere between those two vectors right?
 
  • #6
nothingislost said:
ok i see and the total force necessary would just be the tangential and the centripetal forces, basically somewhere between those two vectors right?

Yes. :smile:
 
  • #7
:smile:
 
  • #8
nothingislost said:
A carousel going counter clockwise starts from rest and accelerates at a constant angular acceleration of 0.02 rev/s^2. A girl sitting on a bench on the platform 7 m from the center is holding a 3kg ball. Calculate the magnitude and the direction of the force she must exert to hold the ball 6s after the carousel starts to move. Give the direction with respect to the line from the center of rotation to the girl.

So the moving carousel simply creates an effective force on the ball opposite its rotation. I think the only force is mw^2r, where m is the mass on the ball w is the angular velocity and r is distance from the center of rotation to the girl. Is this right? the direction of the force the girl puts on the ball is opposite the natural force and tangent the the motion. I am getting .3024 N but this seems very small.
thanks

The most practical approach, I think, is to decompose the vector for the required force in a tangential component and a radial component.

The tangential component
The carrousel undergoes uniform angular acceleration. To maintain the same position of the ball with respect to the carrousel a tangential force on the ball is necessary. This force will keep the ball co-rotating with the carrousel, without it the ball would lag behind. Since the carrousel's angular acceleration is constant, and the distance to the central axis of rotation is constant, the required tangential force is constant.

The radial component
At each point in time an inward force is required to maintain the same radial distance. The expression for required centripetal force is known to you.

The total required force to prevent the ball from moving with respect to the carrousel is the vector sum of the tangential and radial component.

(Not every problem that involves a carrousel and a ball is about Coriolis effect. In this particular case it would be very, very unpractical to try and frame the problem in terms of some Coriolis effect.)

Cleonis
 
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Related to Coriolis effect, a girl on holding a ball on a carousel

1) How does the Coriolis effect affect the trajectory of a ball held by a girl on a moving carousel?

The Coriolis effect is an apparent deflection of moving objects on the surface of the Earth due to the Earth's rotation. In the case of a girl holding a ball on a carousel, the ball will appear to curve to the right or left depending on the direction of the carousel's rotation. This is because the ball maintains its inertia while the carousel and the girl holding it are rotating.

2) Does the Coriolis effect only affect objects on Earth?

No, the Coriolis effect can also be observed on other rotating bodies in space, such as other planets or even hurricanes on Earth. However, it is most prominent on the Earth's surface due to its large size and relatively fast rotation.

3) How does the speed of the carousel affect the Coriolis effect on the ball?

The faster the carousel is spinning, the more pronounced the Coriolis effect will be on the ball. This is because the higher the speed, the greater the force that is acting on the ball due to its inertia.

4) Is the Coriolis effect responsible for creating the spin of hurricanes?

The Coriolis effect does play a role in the development of hurricanes, but it is not the sole factor. The rotation of the Earth, along with other atmospheric conditions, contribute to the formation of hurricanes.

5) Does the Coriolis effect affect the trajectory of all moving objects on Earth?

Yes, all objects on the Earth's surface are subject to the Coriolis effect to some degree. However, the effect is only noticeable for objects moving over long distances or for extended periods of time, such as missiles, airplanes, and weather patterns.

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