Convergence or Divergence of Series with Square Roots

In summary, the conversation was about determining whether the series \sum (\sqrt {k} - \sqrt {k - 1})^k converges or diverges. The conversation included the use of the root test, where the limit of the general term was found to be 0, indicating that the series converges. The conversation also touched on the use of the comparison test, where it was noted that the series whose general term is 1/sqrt(k) diverges, but this was not relevant to the current series being tested. Overall, it was concluded that the series converges.
  • #1
zeion
466
1

Homework Statement



Determine whether the series converges or diverges.

[tex]\sum (\sqrt {k} - \sqrt {k - 1})^k[/tex]


Homework Equations





The Attempt at a Solution



[tex](a_k)^\frac{1}{k} = \sqrt{k} - \sqrt{k - 1} [/tex]

What do I do here..?

[tex]= \frac{1}{\sqrt{k} + \sqrt{k-1}} \to 0 ?[/tex]
 
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  • #2
I would start with this:
[tex]\sqrt{k} - \sqrt{k - 1} = \frac{(\sqrt{k} - \sqrt{k - 1})(\sqrt{k} + \sqrt{k - 1})}{\sqrt{k} + \sqrt{k - 1}}[/tex]
 
  • #3
So that is
[tex]
\sqrt{k} - \sqrt{k - 1} = \frac{(\sqrt{k} - \sqrt{k - 1})(\sqrt{k} + \sqrt{k - 1})}{\sqrt{k} + \sqrt{k - 1}}
= \frac {\sqrt{k}^2 - \sqrt{k-1}^2}{\sqrt{k} + \sqrt{k - 1}} = \frac{1}{\sqrt{k} + \sqrt{k-1}} [/tex]
 
  • #4
Then

[tex]\frac{1}{\sqrt{k} + \sqrt{k-1}} < \frac{1}{\sqrt{k}} = ( \frac{1}{k})^{\frac{1}{2} [/tex]? then converges?
 
  • #5
You are apparently confusing yourself. You started with the root test, not the comparison test.

BTW, the series whose general term is 1/sqrt(k) diverges, but that's not relevant to what you're doing.
 
  • #6
Ok so I go here [tex]\frac{1}{\sqrt{k} + \sqrt{k-1}}[/tex] and then I'm kinda stuck
 
  • #7
Take the limit as k --> infinity. What do you get? Why is this limit important to you? What did you start out doing in your first post?
 
  • #8
I get 0? So the ratio is < 1 so its converges?
 
  • #9
The limit is < 1. Try not to confuse yourself into think you are working with the ratio test - here it's the root test, so the fact that you are finding the limit of a fraction is not relevant.
 
  • #10
Ok so since [tex]a_k < \mu^k[/tex] and [tex] \mu^k[/tex] converges [tex] a_k [/tex]converges
 
  • #11
I don't know -- what's [itex]\mu[/itex]? That's the first time it has appeared in this thread.

zeion, you need to step back and take a bigger-picture view of what you're doing. You seem to be getting lost in minute details, and losing track of the purpose of the details.

Maybe it will help you grasp the overall strategy by answering these questions.
  1. What test are you using?
  2. When you use this test, what result indicates that the series you're testing converges?
    What result indicates that the series diverges?
  3. What result did you get?
  4. What can you conclude about the series you are testing?
 

Related to Convergence or Divergence of Series with Square Roots

1. What is the series root or ratio test?

The series root or ratio test is a mathematical method used to determine the convergence or divergence of a series. It involves calculating the limit of the n-th root or ratio of consecutive terms of the series as n approaches infinity.

2. How do you perform the series root or ratio test?

To perform the series root or ratio test, you need to take the limit of the n-th root or ratio of consecutive terms of the series as n approaches infinity. If the limit is less than 1, the series converges. If the limit is greater than 1, the series diverges. If the limit is equal to 1, the test is inconclusive and another method must be used.

3. When do you use the series root test and when do you use the series ratio test?

You use the series root test when the series contains terms raised to a power, such as n-th power, factorial, or exponential. You use the series ratio test when the series contains terms in the form of a geometric progression, where each term is multiplied by a common ratio.

4. What is the difference between the series root test and the series ratio test?

The main difference between the series root test and the series ratio test is the type of series they are used for. The series root test is used for series with terms raised to a power, while the series ratio test is used for series with terms in the form of a geometric progression. They both involve taking the limit of the n-th root or ratio of consecutive terms as n approaches infinity to determine convergence or divergence.

5. Can the series root or ratio test determine the exact value of a convergent series?

No, the series root or ratio test can only determine the convergence or divergence of a series. It cannot determine the exact value of a series. To find the exact value, you may need to use other methods such as the integral test or comparison test.

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