Constant Volume Mixing Problem

In summary, Pawtucket Pat tinkers with the recipe of Perma-SudsTM beer by filling a tank with 200 L of beer concentrate and pumping in carbonated liquid at a rate of 2 L/min. The amount of carbonated liquid in the tank at any time t can be calculated using the equation Q(t) = 200c(1-e-t/100). The beer becomes unsafe to drink once the concentration of carbonated liquid reaches 50%, and it takes approximately 41.7 minutes for the concentration to reach this level. However, at t=60 minutes, the amount of carbonated liquid present is only 90.2c, making the beer safe to drink without causing Peter and Brian to float to the
  • #1
lionsgirl12
6
0
1. After seeing Peter and Brian Griffin's reaction to Perma-SudsTM (the beer that never goes flat), Pawtucket Pat decides to tinker with the beer's recipe. He starts by filling a tank with 200 L of beer concentrate. Pressurized carbonated liquid (concentration = 100%, of carbonation's solubility in the given temperature and pressure) is then pumped into the tank at a rate of 2 L/min, and the well-mixed solution is drawn off at the same rate to be bottled.

(a) Find the amount of carbonated liquid in tank at any time t.

(b) The Perma-SudsTM beer becomes unsafe to drink once the concentration of carbonated liquid reaches 50% or higher. Is the bottle filled at t=60 minutes safe to drink? (Or, will Peter and Brian float to the ceiling upon drinking it?)

(c) Find the exact time the concentration of carbonated liquid inside the tank reaches 50% of its solubility.




2.
(a)Q(t): amount of carbonated liquid present at any time t

Q(0) = 0 : original amount of liquid in tank

r0=ri=r=2 L/min

c=? ( i do not know how to interpret the concentration in this problem )

2c is the amount of carbonated liquid leaving in 1 min

ds/dt = 2c-(2Q/200) Q(0)=0
0=2c-(2Q/200)
Q=200c

Q(t) = 200c(1-e-t/100)
Q(t) = 200c as t approaches infinity


(b)Q(t) = 200c(1-e-60/100)
Q(t) = 90.2c


 
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  • #2
Since 90.2c is less than 50c, the beer is safe to drink. Peter and Brian will not float to the ceiling upon drinking it.(c)Q(t) = 50c50c = 200c(1-e-t/100)1-e-t/100 = 0.25e-t/100 = 0.75 -t/100 = ln0.75t = -100ln0.75t ≈ 41.7min
 

Related to Constant Volume Mixing Problem

1. What is the Constant Volume Mixing Problem?

The Constant Volume Mixing Problem refers to a situation in which two or more substances are mixed together in a container with a fixed volume. This problem is commonly encountered in chemistry and other scientific fields, as well as in everyday life.

2. Why is the Constant Volume Mixing Problem important?

The Constant Volume Mixing Problem is important because it allows scientists to study the behavior of substances when they are mixed together in a controlled manner. This can provide valuable insights into chemical reactions and other processes that occur during mixing.

3. How do you solve the Constant Volume Mixing Problem?

The Constant Volume Mixing Problem can be solved using various mathematical models and equations, such as the ideal gas law or the law of conservation of mass. The specific method used will depend on the properties of the substances being mixed and the conditions of the mixing process.

4. What factors can affect the outcome of the Constant Volume Mixing Problem?

Several factors can influence the outcome of the Constant Volume Mixing Problem, including the initial concentrations of the substances, the temperature and pressure of the system, and any chemical reactions that may take place during mixing. The size and shape of the container may also play a role.

5. What are some real-world applications of the Constant Volume Mixing Problem?

The Constant Volume Mixing Problem has many practical applications, such as in the production of medicines, the brewing of beer, and the mixing of fuels in engines. It is also used in environmental studies to model the mixing of pollutants in bodies of water and the atmosphere.

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